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18x-6=5x^2+5x
We move all terms to the left:
18x-6-(5x^2+5x)=0
We get rid of parentheses
-5x^2+18x-5x-6=0
We add all the numbers together, and all the variables
-5x^2+13x-6=0
a = -5; b = 13; c = -6;
Δ = b2-4ac
Δ = 132-4·(-5)·(-6)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-7}{2*-5}=\frac{-20}{-10} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+7}{2*-5}=\frac{-6}{-10} =3/5 $
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